2^(t/28)=16

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Solution for 2^(t/28)=16 equation: 



2^(t/28)=16

We move all terms to the left:

2^(t/28)-(16)=0

We add all the numbers together, and all the variables

2^(+t/28)-16=0

We multiply all the terms by the denominator


2^(+t-16*28)=0

We add all the numbers together, and all the variables

2^(t-448)=0

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